Help with Polynomial Long Division

[maxte]

The problem:

m-2/2m^2+m-10

Mathway said the answer is 2m+5 but i cant seem to get that answer. The answer I always get is 2m-3+ 16/m-2

I know i'm missing something here so help me out, please!

 

[JeffM]

The problem:

m-2/2m^2+m-10

Mathway said the answer is 2m+5 but i cant seem to get that answer. The answer I always get is 2m-3+ 16/m-2

I know i'm missing something here so help me out, please!

First, the problem you posed is

\(\displaystyle m - \dfrac{2}{2} * m^2 + m - 10 = m - 1 * m^2 + m - 10 = - m^2 + 2m - 10.\)

If the problem is (2m^2 + m - 10) / (m - 2), then the correct answer is:

\(\displaystyle \dfrac{2m^2 + m - 10}{m -2} = \dfrac{(2m + 5)(m - 2)}{m -2} = 2m + 5.\)

If the problem is (m - 2) / (2m^2 + m - 10), then the correct answer is:

\(\displaystyle \dfrac{m - 2}{2m^2 + m - 10} = \dfrac{m - 2}{(2m + 5)(m - 2)} = \dfrac{1}{2m + 5}.\)

What is the exact problem, and please be careful to follow proper order of operations (PEMDAS) with proper grouping symbols.

EDIT: Fixed typo shown in denis's post below. I KNEW he wanted company in the corner.

 

[maxte]

That is very BADLY posted; problem should be shown this way:
(2m^2 + m - 10) / (m - 2) ; make sure you understamd why brackets are required...

Then the work is done this way:

      2m
     ---------------
m-2 / 2m^2 +  m - 10
      2m^2 - 4m

I've shown you the 1st step.
If you can't finish it, you need classroom help...

Yea sorry about that. I figured out why i was getting -3 instead of 5, i was subtracting m-4m instead of m- -4m.

Thanks for the help!