Abstract Algebra

jose12v

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Prove that 2Z/10Z is isomorphic to Z5 as an abelian group

Prove that 2Z/10Z cannot possibly be isomorphic to Z5 as a ring.
 
You mean Z10/Z2, don't you? Or perhaps you are using a different notation than I am use to. Z10 can be characterized as 10 equivalence classes, labeled 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. Modulo Z2 removes the "odd" labeled classes.

For the second part, note that 5 is prime so Z5 has no "zero-divisors". In Z10, 2(5)= 0 so 2 and 5 are "zero-divisors". What about "modulo 2"?
 
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