trigonometry

[magipson25]

please help cosa / 1-sin a=? suppose cot(x)= - 1/3 and angle(x) lies in quadrant2, find sin(x) and cos(x)

 

[stapel]

please help cosa / 1-sin a=? suppose cot(x)= - 1/3 and angle(x) lies in quadrant2, find sin(x) and cos(x)

Is this one exercise, or two? Either way, what have you tried so far? Where are you stuck?

Please be complete. Thank you!

 

[Deleted member 4993]

please help cosa / 1-sin a=? suppose cot(x)= - 1/3 and angle(x) lies in quadrant2, find sin(x) and cos(x)

I assume that the first problem is:

\(\displaystyle \dfrac{cos(α)}{1-sin(α)} \ = \ ?\)

If it is then it should have been written as

cos(a) / [1-sin(a)]=?

Those brackets are very important!!

Hint:

multiply the numerator and the denominator by [1 + sin(α)]

\(\displaystyle \dfrac{cos(α)}{1-sin(α)} \ = \ \dfrac{cos(α)[1+sin(α)]}{[1-sin(α)][1+sin(α)]} \ = \ ?\) ..... continue....