\(\displaystyle \frac{dy}{dx}= 4x^{1/2}\) soy'=4*x^(1/2)
\(\displaystyle \frac{dy}{dx}= 4y^{1/2}\) soand y'=4*y^(1/2)
Now integrate.I dont even know how to start :/
...\(\displaystyle \frac{dy}{dx}= 4y^{1/2}\) so
\(\displaystyle y^{-1/4}dy= 4dx\)
Now integrate.