cc.5.nbt.6 Problem Solving

kar

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Can't figure this out. Jon caught four fish that weighed a total of 252 pounds, The king fish weighed twice as much as the amberjack and the white marlin weighed twice as much as the kingfish. The weight of the tarpon was five times the weight of the amberjack. How much did each fish weigh?
 
Can't figure this out. Jon caught four fish that weighed a total of 252 pounds, The king fish weighed twice as much as the amberjack and the white marlin weighed twice as much as the kingfish. The weight of the tarpon was five times the weight of the amberjack. How much did each fish weigh?

Let

the weight of the Kingfish = K

the weight of the Amberjack = A The king fish weighed twice as much as the amberjack → K = 2*A

the weight of the Merlin = M marlin weighed twice as much as the kingfish → M = 2 * K = 4 * A

the weight of the Tarpon = T The weight of the tarpon was five times the weight of the amberjack → T = 5 * A

Jon caught four fish that weighed a total of 252 pounds → K + A + M + T = 252

Now continue.....
 
Thanks. I used the equation: a + 2a + 4a + 5a = 252.
12a = 252
12 12
a = 21

Amberjack = 21 lbs Kingfish = 42 lbs White Marlin = 84 lbs Tarpon = 105 lbs
 
"Last edited by Subhotosh Khan; Today at 09:48 PM.
Reason: Denis is in the corner - so I corrected it for him"

Well, 256 was better: a square :idea:

No!! π are square - and on top of that 12 is not an integer factor of 256 (i.e. the answers would be ugly.)
 
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