Odd trinomial problem

gcooper

New member
Joined
Oct 19, 2014
Messages
22
A ball is thrown upward with an initial speed of 80 feet per second. The height (h) of the ball is given by the formula h = vt - 16t^2 where v is the initial speed and t is the time in seconds. How many second will it take for the ball to reach the ground?

So, when the ball is on the ground, the height is 0, therefore:

0 = 80t - 16t^2

changing signs, we get:

16t^2 - 80t = 0;

That's where I get stuck, because the last term which would be a b^2, is 0 here! How am I supposed to factor & solve this?
 
A ball is thrown upward with an initial speed of 80 feet per second. The height (h) of the ball is given by the formula h = vt - 16t^2 where v is the initial speed and t is the time in seconds. How many second will it take for the ball to reach the ground?

So, when the ball is on the ground, the height is 0, therefore:

0 = 80t - 16t^2

changing signs, we get:

16t^2 - 80t = 0;

That's where I get stuck, because the last term which would be a b^2, is 0 here! How am I supposed to factor & solve this?

In here, b = -80 and A = 16 and C = 0
 
Top