A ball is thrown upward with an initial speed of 80 feet per second. The height (h) of the ball is given by the formula h = vt - 16t^2 where v is the initial speed and t is the time in seconds. How many second will it take for the ball to reach the ground?
So, when the ball is on the ground, the height is 0, therefore:
0 = 80t - 16t^2
changing signs, we get:
16t^2 - 80t = 0;
That's where I get stuck, because the last term which would be a b^2, is 0 here! How am I supposed to factor & solve this?
So, when the ball is on the ground, the height is 0, therefore:
0 = 80t - 16t^2
changing signs, we get:
16t^2 - 80t = 0;
That's where I get stuck, because the last term which would be a b^2, is 0 here! How am I supposed to factor & solve this?