mynamesmurph
Junior Member
- Joined
- Aug 10, 2014
- Messages
- 51
x=cos3t
y=sin3t
Any hints?
y=sin3t
Any hints?
x=cos3t
y=sin3t
Any hints?
Wouldn't it be better to just go ahead and write \(\displaystyle x^{2/3}= cos^2(t)\) and \(\displaystyle y^{2/3}= sin^2(t)\)Like this?
x2/3=(cos3t)2/3
y2/3=(sin3t)2/3
I would probably have left it as \(\displaystyle y^{2/3}+ x^{2/3}= 1\)3[/SUP]√(y2) + 3√(x2)=cos2t+sin2t
3√(y2) + 3√(x2)=1
Using Latex, [ tex ]\sqrt[n]{x}[ tex ], without the spaces, gives \(\displaystyle \sqrt[n]{x}\).Edit: Is there a better way to write "nth" roots on this forum?
Like this?
x2/3=(cos3t)2/3
y2/3=(sin3t)2/3
3√(y2) + 3√(x2)=cos2t+sin2t
3√(y2) + 3√(x2)=1
Edit: Is there a better way to write "nth" roots on this forum?