Please help me to solve this

[Amanda30]

\(\displaystyle \displaystyle{ \sum_{n\, =\, 1}^{\infty} \,}\)\(\displaystyle \dfrac{4n^3}{6^{n+1}}\)

How to find a_1, a₂, a_3. ​Is this function convergent and explain how?

 

[Deleted member 4993]

\(\displaystyle \displaystyle{ \sum_{n\, =\, 1}^{\infty} \,}\)\(\displaystyle \dfrac{4n^3}{6^{n+1}}\)

How to find a_1, a₂, a_3. ​Is this function convergent and explain how?

What are your thoughts?

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[stapel]

\(\displaystyle \displaystyle{ \sum_{n\, =\, 1}^{\infty} \,}\)\(\displaystyle \dfrac{4n^3}{6^{n+1}}\)

How to find a_1, a₂, a_3. ​Is this function convergent and explain how?

What are "a₁", "a₂", and "a₃"? Are they the first three summation terms (summing from n = 1 to n = 1, from n = 1 to n = 2, and from n = 1 to n = 3)? Or are they the addends of the series (so the sum from n = 1 to n = 3 is a₁ + a₂ + a₃)? Or something else?

You have posted a summation. To what "function" are you making reference? Or did the instructions actually as if the "series" is convergent?

What are your thoughts? What rules, methods, or other tools have they given you? How far have you gotten in applying them? Where are you stuck? How are you expected to apply the techniques and concepts of differential equations to this algebra question?

Please be complete. Thank you!