I'm having trouble proving there are no solutions to a^n + b^n = c^n for n>2

[Pierre de Fermat]

I'm having trouble proving there are no solutions to the following equation. Little help?

a ⁿ + b ⁿ = c ⁿ

(Where n is greater than 2)

 

[stapel]

I'm having trouble proving there are no solutions to the following equation. Little help?

a ⁿ + b ⁿ = c ⁿ

(Where n is greater than 2)

Ha. Ha. :roll:

 

[Deleted member 4993]

I'm having trouble proving there are no solutions to the following equation. Little help?

a ⁿ + b ⁿ = c ⁿ

(Where n is greater than 2)

And 'a' , 'b' & 'c' are any number (real/imaginary, rational/irrational, positive/negative)??

 

[jonah2.0]

Beer soaked ramblings follow.

I'm having trouble proving there are no solutions to the following equation. Little help?

a ⁿ + b ⁿ = c ⁿ

(Where n is greater than 2)

Mon Dieu Monsieur Pierre de Fermat, didst thou perhaps bump thy head and forgot what you wrote as your Last Theorem in the margin of your copy of the Arithmetica next to Diophantus’ sum-of-squares problem:
"It is impossible to separate a cube into two cubes, or a fourth power into two fourth powers, or in general, any power higher than the second, into two like powers. I have discovered a truly marvellous proof of this, which this margin is too narrow to contain."

I be certain a bottle of brandy is enough to jog thy memory.
You'll thank me later.
Maybe you can reclaim thy honor from that young British chap Dr. Andrew Wiles and finally replace his extremely long proof with thy marvellous proof.