sensational
New member
- Joined
- Jun 4, 2015
- Messages
- 21
Z is a random variable representing the standard normal distribution.
You are required to use the accompanying statistical table to answer these questions.
1. Find K such that P(0 < Z < 2k + 1)=0.4112.
By using the standard normal distribution I found out that 2k+1=1.348
finding k will gives 0.174.
I don't know what is wrong with my answer but the real answer is 1.734. Maybe theres something wrong with my z-value which is 1.348 but in my own understanding my z-value is correct since 1.34 has the probability of 0.4099 so we need 0.0013 or 13 in the diffrences column which falls on the 8th column of the differences so the final z-value is 1.348. PLEASE help me figure out whats wrong with my working out.
You are required to use the accompanying statistical table to answer these questions.
1. Find K such that P(0 < Z < 2k + 1)=0.4112.
By using the standard normal distribution I found out that 2k+1=1.348
finding k will gives 0.174.
I don't know what is wrong with my answer but the real answer is 1.734. Maybe theres something wrong with my z-value which is 1.348 but in my own understanding my z-value is correct since 1.34 has the probability of 0.4099 so we need 0.0013 or 13 in the diffrences column which falls on the 8th column of the differences so the final z-value is 1.348. PLEASE help me figure out whats wrong with my working out.