lim(x->-){[e^(2x+1)]/(e^2x)+1}
As posted the function looks like:
\(\displaystyle \dfrac{e^{2x+1}}{e^{2x}+1}\)
Is that correct?
You can use basic algebra to try to break things apart a little:I'm sorry but that " + 1 " is included in the denominator.
\(\displaystyle \dfrac{e^{2x+1}}{e^{2x}+1}\)
Can you help me?
lim(x->-){[e^(2x+1)]/(e^2x)+1)}