Find the smallest number that has of factors of 2, 3, 4, 5, 6, 7, 8 ,9 ,10
- Thread starter rjravaz
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As you saw, that's not how this site works; we don't "do" students' work for them, nor do we give out the answers. For further information, please re-read the "Read Before Posting" announcement.
If the number has all of these values as factors, then the number is of the form 2*a = 3*b = 4*c = ... and so forth. In other words, it has all of these values in some form of its factorization. For instance, 2, 3, 4, 6, and 12 are factors of 12, because 2*6 = 12, 3*4 = 12, and 1*12 = 12. In other words, your target number is a multiple, in some manner, of each of these factors. Since it contains each of these factors, in some manner, this multiple is common to each of these factors.
If you're talking about the smallest number having all of these factors, then you have to consider duplicates. For instance, 2 is a factor of 4, 6, and 12; and 3 is a factor of 6 and 12. So you're looking for the least such number.
Hint: Consider the italicised words above. Where does this lead? (here)
pka
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That is incorrect.
Can you explain why both \(\displaystyle 2^3~\&~3^2\) must be factors of the product?
What other factors are necessary? Please tell us along with your reasoning.
Hint: There are just two others.
