Y=(x^2+x)/ sqrt (x^3+x^2)
D Deleted member 4993 Guest Sep 23, 2016 #2 Mullandowski said: Y=(x^2+x)/ sqrt (x^3+x^2) Click to expand... What is the definition of the range of a function?
Mullandowski said: Y=(x^2+x)/ sqrt (x^3+x^2) Click to expand... What is the definition of the range of a function?
Harry_the_cat Elite Member Joined Mar 16, 2016 Messages 3,693 Sep 23, 2016 #3 Consider simplifying the expression first. \(\displaystyle \dfrac{x^2+x}{\sqrt{x^3+x^2}} = \) \(\displaystyle \dfrac{x(x+1)}{abs(x)\sqrt{x+1}}\) Last edited: Sep 23, 2016
Consider simplifying the expression first. \(\displaystyle \dfrac{x^2+x}{\sqrt{x^3+x^2}} = \) \(\displaystyle \dfrac{x(x+1)}{abs(x)\sqrt{x+1}}\)