Bodmas: 45 +10+[{8-(7-4)+3}*2^2]-7*27÷3= ?

[shilpa]

Bodmas: 45 +10+[{8-(7-4)+3}*2^2]-7*27÷3= ?

Can some one please help us give the correct answer for the below problem

45 +10+[{8-(7-4)+3}*2²]-7*27÷3= ???

 

[Deleted member 4993]

Can some one please help us give the correct answer for the below problem

45 +10+[{8-(7-4)+3}*2²]-7*27÷3= ???

Just for clarification: BODMAS is equivalent to PEMDAS.

B - Brackets (Prenthese)
O - OR (I haven't seen this operator being used in numerical expression after my middle school days in India)
D - Division
M - Multiplication
A - Addition
S - Subtraction

 

[stapel]

Can some one please help us give the correct answer for the below problem

45 +10+[{8-(7-4)+3}*2²]-7*27÷3= ???

We'll be glad to help you with the order-of-operations exercise! (here)

Please reply with a clear listing of your thoughts and efforts so far, so we can try to help you get going again. Thank you!

 

[shilpa]

SO, According to you what is the answer of this probelm
Is it 0 (Zero) or something else

 

[stapel]

SO, According to you what is the answer of this probelm
Is it 0 (Zero) or something else

It's definitely one of those!

Kindly please reply with a clear listing of your thoughts and efforts so far, so we can see what you're doing and where things start to bog down. Then we can provide useful assistance. Thank you!

 

[Ishuda]

Can some one please help us give the correct answer for the below problem

45 +10+[{8-(7-4)+3}*2²]-7*27÷3= ???

If you would like a review you might try
https://www.mathsisfun.com/operation-order-bodmas.html