Random variable distribution: X=0 : P(0)=0.849; X=1 : P(1)=0.145; X=2 : P(2) = 0.005

MathLearner2016

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2 cards are drawn from a 52 card deck. The random variable X represents the number of aces drawn. The random variable distribution:
X = 0 : P(0) = 0.849
X = 1 : P(1) = 0.145
X = 2 : P(2) = 0.005

Is this how you do it?

Probability of the draws:

0 aces out of 2 cards:

C(48,2) * C(4,0) / C(52,2)

1128 / 1328 = 0.849

1 ace out of 2 cards:

C(48,1) * C(4,1) / C(52,2)

48 * 4 / 1328 = 0.145

2 aces out of 2 cards:

C(48,0) * C(4,2) / C(52,2)

6 / 1328 = 0.005
 
2 cards are drawn from a 52 card deck. The random variable X represents the number of aces drawn. The random variable distribution:
X = 0 : P(0) = 0.849
X = 1 : P(1) = 0.145
X = 2 : P(2) = 0.005

Is this how you do it?

Probability of the draws:

0 aces out of 2 cards:

C(48,2) * C(4,0) / C(52,2)

1128 / 1328 = 0.849

1 ace out of 2 cards:

C(48,1) * C(4,1) / C(52,2)

48 * 4 / 1328 = 0.145

2 aces out of 2 cards:

C(48,0) * C(4,2) / C(52,2)

6 / 1328 = 0.005
Yes, hypogeometric is the way to go and your set ups are all correct. Good job!
 
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