Chriscasper
New member
- Joined
- Dec 6, 2016
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- 1
In 0.38. = - 0.9676
need help with steps so I can understand it.
need help with steps so I can understand it.
In 0.38. = - 0.9676
ln(a) = b is the same statement as e^b = a. There is NOTHING to understand in that statement as it is just a definition. For the record ln (a) is short hand for loge(a). So your equation ln 0.38. = - 0.9676 is just saying that e-.9676=0.38.In 0.38. = - 0.9676
need help with steps so I can understand it.
\(\displaystyle \displaystyle e=\sum _{n=0}^{\infty }\:\frac{1}{n!}=\frac{1}{1}+\frac{1}{1\cdot 2}+\frac{1}{1\cdot 2\cdot 3}+...\approx 2.71828\)
That should be
\(\displaystyle \displaystyle e \ = \ \sum _{n=0}^{\infty }\:\frac{1}{n!} \ = \ \frac{1}{1} + \frac{1}{1}+\frac{1}{1\cdot 2}+\frac{1}{1\cdot 2\cdot 3} \ + \ ... \ \approx \ 2.71828\)
And 1/1! minutes in the corner.Ah yes, you're correct. I forgot about the 0 factorial term. Thanks for pointing it out to me, I'll edit my post accordingly.