Algebraic fraction: If x > 2, then x^2-x-6/x^2-4 = ?

[gpeight]

If x > 2, then x^2-x-6/x^2-4 =

A. x-3/2
B. x-3/x-2
C. x-3/x+2
D. 3/2

The answer is supposed to be B. I don't understand why. I looked through my Algebra I book but can't find anything like this. What am I missing?

Thanks for any help,
Gpeight,

 

[Loren]

Re: Algebraic fraction question

>If x > 2, then x^2-x-6/x^2-4 = \(\displaystyle x^2-x-\frac{6}{x^2}-4\).

Or do you mean (x^2-x-6)/(x^2-4)=\(\displaystyle \frac{x^2-x-6}{x^2-4}\) ?

Please use grouping symbols to clarify what is meant.

 

[Denis]

Re: Algebraic fraction question

If you mean the 2nd one that Loren is showing, then simply factor the numerator and denominator;
a term will cancel out and you'll be left with answer b.

 

[gpeight]

Sorry about missing the grouping symbols. I did mean the second one that Loren posted. Thanks for the explanation, Denis. I get it now.
Gpeight