double checking final answers

[mathshelpplease]

S3 = 9, S6 = 1

3. (a) [math](9+1)x + 2y=5[/math][math]y=-5x+5/2[/math]
[math]3y-x=10-1[/math][math]y=1/3x+3[/math]
--> one solution as the two lines intersect once

(b) [math]3y=x+9[/math][math]x=3y-9[/math]
[math]2y=-10x+5[/math][math]2y=-10(3y-9)+5[/math][math]y=95/32[/math][math]x=-3/32[/math]
(c)
[math]15x+2y=145/32[/math][math]y=-15/2x+145/64[/math]for there to be a solution, must go through (-3/32, 95/32)
as [math]95/32≠-15/2(-32/32)+145/64[/math]there is no solution

(d) intersection must be at (-3/32, 95/32)
[math]a(-3/32)+(95/32)=b[/math][math]f(a) = 95/32-3/32a[/math]

 

[Otis]

S3 = 9, S6 = 1

double checking final answers

Hi. I've inferred that the values for S₃ and S₆ above were given to you.

Everything looks good, except your conclusion in 3(c). It appears that you've substituted -32/32 for x.

?

 

[mathshelpplease]

Hi. I've inferred that the values for S₃ and S₆ above were given to you.

Everything looks good, except your conclusion in 3(c). It appears that you've substituted -32/32 for x.

?

thank you!