Equation of a line with slope and y-intercept

[Ihatealgebra]

Write the equation of the line with given slope and y-intercept.
Slope: -3/4 ; y-intercept: (0,8)
I come up with y=-3/4x+8
My problem is showing how I came up with that.

 

[jwpaine]

You are correct.
You know that your y-intercept is 8
You know your slope is (-3/4)

you know that the slope-intercept form of a line is expressed by y=mx+b

So your equation y=mx+b is y= (-3/4)x + 8


Also, Using point-slope form of the line: \(\displaystyle \large y-y1=m(x-x1)\)
\(\displaystyle y-8=(-3/4)(x-0)\)
\(\displaystyle y=(-3/4)x + 8\)