Did it! and got correct answers! would you mind checking my process though? Especially the second picture. I got sqrt -1 so I hope I made no mistakes there.
I don't think you addressed #2 from my reply. And the square root of -1? Now we are dealing with complex numbers.
I thought that just mean given a condition that RHS must be =>0 if LHS is a sqrt. And although I got sqrt - 1 i was able to get rid of the sqrt
What??
Their domains are not the same.
I would like to do this without graphs. I don't know what you mean by evaluate using - 2?Their domains are not the same.
For an example, evaluate each using [imath]x=-2[/imath].
Or, compare their graphs.
Evaluate with x=-2
I cannot seem to find a word for evaluate in my language so I am not sure what it means... The best translation I can find is "try to guess" and I that's not really helping me so could you try wording it a bit differently.
Evaluate a function at a point means calculate the value of the function at that point.
Why would I do that?
You'll see that one expression is defined at -2, the other isn't, so their domains are not the same.
Okay... How do I get - 2?
I'd suggested -2 only because it's the first negative value that I'd thought of in the domain you'd found (post #1). But you could evaluate the two expressions in post #5 using any negative number because any negative value for x will show that those two expressions are not always the same. They are the same if and only if [imath]x\ge1[/imath].