James10492
Junior Member
- Joined
- May 17, 2020
- Messages
- 50
Hi there,
I have come across a problem I don't know how to solve and I would really appreciate if someone could shed some light.
2^(x+3) = 2^x + 3
Now in the exercise book it gives you the hint that you should write 2^x = k (where k is a real number), so
2^x = 2^(x+3) - 3
2^x = k
now take natural logs
ln 2^x = ln k
x ln 2 = ln k
x = ln k / ln 2
The solution to the problem is in fact ln (3/7) / ln 2 , but I cannot see how ln k has become ln (3/7). I am definitely missing something here, any help would be much appreciated.
I have come across a problem I don't know how to solve and I would really appreciate if someone could shed some light.
2^(x+3) = 2^x + 3
Now in the exercise book it gives you the hint that you should write 2^x = k (where k is a real number), so
2^x = 2^(x+3) - 3
2^x = k
now take natural logs
ln 2^x = ln k
x ln 2 = ln k
x = ln k / ln 2
The solution to the problem is in fact ln (3/7) / ln 2 , but I cannot see how ln k has become ln (3/7). I am definitely missing something here, any help would be much appreciated.
