Timothy133
New member
- Joined
- Nov 15, 2020
- Messages
- 1
Hello guys,
I am currently trying to solve this problem, a woman wants to have 2 fields for plants. One of them is circular and one of them squared. The scope of them both combined is 10 -> so 10 = 2*Pi*r + 4*x. This is the secondary condition. The main one is A= Pi*R² + x². I have to solve the problem for the minimum area possible with the scope of 10.
I am stuck
I am currently trying to solve this problem, a woman wants to have 2 fields for plants. One of them is circular and one of them squared. The scope of them both combined is 10 -> so 10 = 2*Pi*r + 4*x. This is the secondary condition. The main one is A= Pi*R² + x². I have to solve the problem for the minimum area possible with the scope of 10.
I am stuck