Hello, I've been wondering for several months, we all know that a² + b² = (a + b)² - 2ab
Now I've always wanted to factorise it because (a + b)² - 2ab is not a factorised expression.
Therefore, I came up with a² + b² = (a + b)² - 2ab = (a + b - √2ab)(a + b + √2ab)
How did I do this? Well, I took into consideration that (a + b)² - 2ab is somewhat the same as x² - y² which is equal to (x - y)(x + y). Therefore, I assigned (a + b)² to 'x' and 2ab to 'y'. So the outcome would be (a + b - √2ab)(a + b + √2ab)
What'd you guys think about this?
Now I've always wanted to factorise it because (a + b)² - 2ab is not a factorised expression.
Therefore, I came up with a² + b² = (a + b)² - 2ab = (a + b - √2ab)(a + b + √2ab)
How did I do this? Well, I took into consideration that (a + b)² - 2ab is somewhat the same as x² - y² which is equal to (x - y)(x + y). Therefore, I assigned (a + b)² to 'x' and 2ab to 'y'. So the outcome would be (a + b - √2ab)(a + b + √2ab)
What'd you guys think about this?