anti-matter
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- Oct 6, 2023
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67.
Find the equation of the line that passes through the following points: (a,0) and (c,d)
Answer 67.
[math]y = \left(\frac{d}{c-a}\right)x - \frac{ad}{c-a}[/math]Hello, I am first time posting to this forum. Without further ado, I need help with this math problem from this website: OpenStax. The problem is # 67. The linear equation is y=mx+b
Work:
Using point slope equation I can get the first part:
[math]y = \left(\frac{d}{c-a}\right)x[/math][math]d-0=m(c-a)[/math]Transposed:
[math]d=m(c-a)[/math][math]\frac{d}{(c-a)}=m[/math]
for mx
but I can't get
[math]- \frac{ad}{c-a}[/math]for +b
My attempt:
[math]d=(\frac{d}{c-a})c+b[/math][math]d=(\frac{dc}{c-a})+b[/math][math]d-(\frac{dc}{c-a})=b[/math]
Not correct.
Find the equation of the line that passes through the following points: (a,0) and (c,d)
Answer 67.
[math]y = \left(\frac{d}{c-a}\right)x - \frac{ad}{c-a}[/math]Hello, I am first time posting to this forum. Without further ado, I need help with this math problem from this website: OpenStax. The problem is # 67. The linear equation is y=mx+b
Work:
Using point slope equation I can get the first part:
[math]y = \left(\frac{d}{c-a}\right)x[/math][math]d-0=m(c-a)[/math]Transposed:
[math]d=m(c-a)[/math][math]\frac{d}{(c-a)}=m[/math]
for mx
but I can't get
[math]- \frac{ad}{c-a}[/math]for +b
My attempt:
[math]d=(\frac{d}{c-a})c+b[/math][math]d=(\frac{dc}{c-a})+b[/math][math]d-(\frac{dc}{c-a})=b[/math]
Not correct.