Find the remainder when 6x square + x 1 is divided by 3x – 1.

[em_Varshini]

solve this

 

[Deleted member 4993]

solve this

Please check your subject line of the post for correctness. As written, it does not make sense.

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520

Please share your work/thoughts about this assignment.

 

[HallsofIvy]

You wrote "6 x square plus x 1". What does the "1" mean in that? Did you intend "plus 1" so that you have "\(\displaystyle 6x^2+ x+ 1\)" to be divided by 3x- 1?

If you are not taking an algebra course where did you get this problem? If you are, surely you should know some basics for dividing a polynomial by a linear term! What have you tried?

Do you know how to do "long division" of numbers? For example, if you were asked to divide 89 by 21, you would observe that 20 divides into 80 4 times so your "trial divisor" would be "20". What would you do then? How many times will 3x divide into \(\displaystyle 6x^2\)?

And please do not just say "solve this". That comes off as bossy and rude!

 

[Alpha2005]

I think aim able to help sir

 

[lookagain]

I think aim able to help sir

Alpha2005, you are not helping by giving full solutions when the asker has
not contributed any work and/or questions toward it. Please do not give
solutions until some of this has happened.

 

[topsquark]

And we aren't sure that [math]6x^2 + x + 1[/math] is correct, anyway.

-Dan