A gold ingot weighs 100.5 lbs. If the density of gold is 19.37g / cm^3 (cubic centimeters) and the length and width of the ingot are 13.8 cm and 2.23 cm, respectively, what is the height of the ingot?
I have been messing with this for quite some time. I know the volume V = L x W x H, and the density D = M / V (mass divided by volume), so V = M / D and M = D x V. I have been filling in what i know and solving it that way but it is still wrong.
Any help appreciated.
I have been messing with this for quite some time. I know the volume V = L x W x H, and the density D = M / V (mass divided by volume), so V = M / D and M = D x V. I have been filling in what i know and solving it that way but it is still wrong.
Any help appreciated.
