Please help... I'm so done with this question ??
Z Zetrics New member Joined Mar 5, 2020 Messages 3 Mar 5, 2020 #1 Please help... I'm so done with this question ?? Attachments 15834102632001758160880.jpg 1.5 MB · Views: 3 Last edited by a moderator: Mar 5, 2020
D Deleted member 4993 Guest Mar 5, 2020 #2 Zetrics said: Please help... I'm so done with this question ?? View attachment 17007 Click to expand... You are going in the right direction. Use the given definition of h(x): \(\displaystyle \ \to \ \) h(x) = p * x + q h[(x-1)^2] = p * (x-1)^2 + q and continue......
Zetrics said: Please help... I'm so done with this question ?? View attachment 17007 Click to expand... You are going in the right direction. Use the given definition of h(x): \(\displaystyle \ \to \ \) h(x) = p * x + q h[(x-1)^2] = p * (x-1)^2 + q and continue......
Dr.Peterson Elite Member Joined Nov 12, 2017 Messages 16,087 Mar 5, 2020 #3 In your work, you dropped the "+ 5" in g, and have not yet applied the definition of h.