The 22 didn't turn into 121. [imath]\Delta[/imath] is the discriminant (actually, 1/4 of the discriminant)Hi
I'm new just here so
In four number line, how minus 22 turn into 121 and number line how get 226 please?View attachment 36610
Hi
I'm new just here so
In four number line, how minus 22 turn into 121 and number line how get 226 please?View attachment 36610
As I read this, they are using [imath]\Delta'[/imath] to mean the discriminant divided by 4, namely [math]\Delta'=\frac{\Delta}{4}=\frac{b^2-4ac}{4}=\frac{b^2}{4}-ac=\left(\frac{b}{2}\right)^2-ac[/math]Hi
I'm new just here so
In four number line, how minus 22 turn into 121 and number line how get 226 please?View attachment 36610
The 22 didn't turn into 121. [imath]\Delta[/imath] is the discriminant (actually, 1/4 of the discriminant)
[imath]a r^2 + b r + c = 0 \implies \Delta = b^2 - 4 a c[/imath]
So, find [imath]\Detla[/imath] and divide by 4 and you get line 3.
The 226 is found by expanding the [imath]3^2 + (11 - 4 \sqrt{6})^2 = 3^2 + 11^2 - 88 \sqrt{6} + 96[/imath].
Just a thought... I'm getting the idea that you haven't learned how to solve Quadratic equations, nor how to FOIL out an expression?
-Dan
You're welcome as alwaysWhat is the meaning of [imath]\Delta'[/imath]? Does it perhaps stand for "the value of the discriminant"? If so, then your value of "121" cannot be correct. (It is 22 that is being squared, not 11.) The value of the square root of [imath]\Delta'[/imath] is correct, however.
What were the instructions for this drawing? Are you supposed to be finding the *shaded* area?
Thank you!
Nice explanation sirb2-4ac = 222 - 4*1*25 = (2*11)2 - 4*25 = 4*121-4*25 = 4(121-25) = 4(96). That is why they use Δ′ as Δ/4
This is a perfect case that shows that one needs to define their variables.
Presumably, wherever the solution came from (and we haven't even been shown the full statement of the problem), [imath]\Delta'[/imath] is a standard notation that was previously defined (e.g. in a textbook).That is why they use Δ′ as Δ/4
This is a perfect case that shows that one needs to define their variables.