How do find to value of x or y so that the line through to point has the given slope?

[xpatel]

Hello community

I have the following coordinates of (x, 6) and (-6, 0) with a slope of 3. How do I find x give a slope value of 3? I keep getting x as 4. I'm something wrong. The equation I am using is y2-y1 = m(x2-x1), but unsure if this the right approach or formula. Thanks for the help

very respectfully
Xita

 

[Deleted member 4993]

Hello community

I have the following coordinates of (x, 6) and (-6, 0) with a slope of 3. How do I find x give a slope value of 3? I keep getting x as 4. I'm something wrong. The equation I am using is y2-y1 = m(x2-x1), but unsure if this the right approach or formula. Thanks for the help

very respectfully
Xita

Please post the EXACT problem (as it was given to you).

 

[pka]

Hello community

I have the following coordinates of (x, 6) and (-6, 0) with a slope of 3. How do I find x give a slope value of 3? I keep getting x as 4. I'm something wrong. The equation I am using is y2-y1 = m(x2-x1), but unsure if this the right approach or formula.

Given $\displaystyle A: (x,6)~\&~B: (-6,0)$ as one 'moves' from $\displaystyle A\to B$ the change in $\displaystyle x$ is $\displaystyle \Delta x=-6-x$ and the change in $\displaystyle y$ is $\displaystyle \Delta y= -6$.

Slope is defined as $\displaystyle m=\dfrac{\Delta y}{\Delta x}=\dfrac{-6}{-6-x}=3$

 

[Otis]

I keep getting x as 4. I'm [doing] something wrong.

Please post your work. Then we can show you what needs correcting. Cheers!