I have to expand log(100/x^2y)^2 but I'm not sure how. does anyone know?
M moth345 New member Joined Apr 24, 2023 Messages 1 Apr 24, 2023 #1 I have to expand log(100/x^2y)^2 but I'm not sure how. does anyone know?
topsquark Senior Member Joined Aug 27, 2012 Messages 2,269 Apr 25, 2023 #2 moth345 said: I have to expand log(100/x^2y)^2 but I'm not sure how. does anyone know? Click to expand... I presume this is [imath]log \left [ \left ( \dfrac{100}{x^2y} \right )^2 \right ] [/imath] If so, then [imath]log \left [ \left ( \dfrac{100}{x^2y} \right )^2 \right ] = log \left [ \dfrac{100^2}{x^4y^2} \right ] [/imath] [imath]= log(100^2) - log(x^4) - log(y^2)[/imath] [imath]= 2 \, log(100) - 4 \, log(x) - 2 \, log(y)[/imath] Or, if you want to take [imath]100 = 10^2[/imath] [imath]= 4 \, log(10) - 4 \, log(x) - 2 \, log(y)[/imath] -Dan
moth345 said: I have to expand log(100/x^2y)^2 but I'm not sure how. does anyone know? Click to expand... I presume this is [imath]log \left [ \left ( \dfrac{100}{x^2y} \right )^2 \right ] [/imath] If so, then [imath]log \left [ \left ( \dfrac{100}{x^2y} \right )^2 \right ] = log \left [ \dfrac{100^2}{x^4y^2} \right ] [/imath] [imath]= log(100^2) - log(x^4) - log(y^2)[/imath] [imath]= 2 \, log(100) - 4 \, log(x) - 2 \, log(y)[/imath] Or, if you want to take [imath]100 = 10^2[/imath] [imath]= 4 \, log(10) - 4 \, log(x) - 2 \, log(y)[/imath] -Dan
Dr.Peterson Elite Member Joined Nov 12, 2017 Messages 16,087 Apr 25, 2023 #3 topsquark said: ... Or, if you want to take [imath]100 = 10^2[/imath] [imath]= 4 \,log(10) - 4 \,log(x) - 2 \,log(y)[/imath] -Dan Click to expand... ... and if "log" means the common logarithm (base 10), you can take it further.
topsquark said: ... Or, if you want to take [imath]100 = 10^2[/imath] [imath]= 4 \,log(10) - 4 \,log(x) - 2 \,log(y)[/imath] -Dan Click to expand... ... and if "log" means the common logarithm (base 10), you can take it further.