I thought the expression we're looking for equals (1-x).(1+x)/x. Then I could do nothing else
E egal New member Joined Jul 13, 2021 Messages 33 Nov 5, 2021 #1 I thought the expression we're looking for equals (1-x).(1+x)/x. Then I could do nothing else
Pedja New member Joined Jul 8, 2021 Messages 35 Nov 5, 2021 #2 Hint: Find the relationship between squares of [imath]x+\frac{1}{x}[/imath] and [imath]\frac{1}{x}-x[/imath] .
Hint: Find the relationship between squares of [imath]x+\frac{1}{x}[/imath] and [imath]\frac{1}{x}-x[/imath] .
E egal New member Joined Jul 13, 2021 Messages 33 Nov 5, 2021 #3 Poliagapitos said: Hint: Find the relationship between squares of [imath]x+\frac{1}{x}[/imath] and [imath]\frac{1}{x}-x[/imath] . Click to expand... Is the answer[math] \sqrt{\smash[b]{221}}[/math]?
Poliagapitos said: Hint: Find the relationship between squares of [imath]x+\frac{1}{x}[/imath] and [imath]\frac{1}{x}-x[/imath] . Click to expand... Is the answer[math] \sqrt{\smash[b]{221}}[/math]?
Pedja New member Joined Jul 8, 2021 Messages 35 Nov 5, 2021 #4 @egal If [imath]x^2=a[/imath] then the value of [imath]x[/imath] is _____?
E egal New member Joined Jul 13, 2021 Messages 33 Nov 5, 2021 #5 Poliagapitos said: @egal If [imath]x^2=a[/imath] then the value of [imath]x[/imath] is _____? Click to expand... square root a?
Poliagapitos said: @egal If [imath]x^2=a[/imath] then the value of [imath]x[/imath] is _____? Click to expand... square root a?
Pedja New member Joined Jul 8, 2021 Messages 35 Nov 5, 2021 #6 @egal [imath]x_{1,2}=\pm \sqrt{a}[/imath]
E egal New member Joined Jul 13, 2021 Messages 33 Nov 5, 2021 #7 Poliagapitos said: @egal [imath]x_{1,2}=\pm \sqrt{a}[/imath] Click to expand... oh! thanks a lot!
J JeffM Elite Member Joined Sep 14, 2012 Messages 7,874 Nov 5, 2021 #8 Or you could just solve for x using the quadratic equation and rationalization of denominators.
