HW HELP!!

nurjaan

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Sep 6, 2021
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If sin(x) = 1/3 and sec(y) = 29/21, where x and y lie between 0 and pi/2, what is cos(x − y)?
 
Please read the forum guidelines.

Use the inverse trig functions arcsin and arcsec on a scientific calculator (or Google), to obtain the measures of x and y in radians.

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If sin(x) = 1/3 and sec(y) = 29/21, where x and y lie between 0 and pi/2, what is cos(x − y)?
If you are required to find exact values (which would be mentioned in the instructions for the exercises), then find sine and cosine for each angle, then use the angle-difference formula for the cosine.

Then please show your work, so we can see where, if at all, you need help.
 
If sin(x) = 1/3 and sec(y) = 29/21, where x and y lie between 0 and pi/2, what is cos(x − y)?
Hint: Use the following identities: [imath]\sec \alpha = \frac{1}{\cos \alpha} \quad ; \quad \sin^2 \alpha + \cos^2 \alpha =1 \quad ; \quad \cos(\alpha - \beta)=\cos \alpha\cos\beta+\sin\alpha\sin\beta[/imath]
 
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