(i,j) element of DFT Matrix

DFT Matrix is:
IMG_20200413_194536.jpg
Here transformation matrix example is for 4 points on the unit circle.
I think value of (i,j) inthe matrix is i^(i*j) where first i is the complex number.
 
Clearly it is NOT "\(\displaystyle i^{ij}\)" because if it were the first row (and column) would be \(\displaystyle i^{1*1}= i\), \(\displaystyle i^{2*1}= -1\), \(\displaystyle i^{3*1}= -i\), and \(\displaystyle i^{4*1}= 1\)!
 
You have the DFT matrix in your post #3. At this point isn't it obvious what the ij entry of the matrix is? For example the (3,2) entry is -1.
 
No, I know that if the Matrix is for \(\displaystyle \Omega_{n}\) then the entries can be calculated with \(\displaystyle ω_{n}^k=e^{-2{\pi}i*k/n}\) but is it possible to find out the entry of some \(\displaystyle \Omega_{n}\) matrix with some fomula if only indices (i,j) are given? sorry for my stupidity.
 
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