How does the solution works with these kind of equations?
A achi_kun New member Joined Oct 20, 2020 Messages 7 Oct 27, 2020 #1 How does the solution works with these kind of equations?
skeeter Elite Member Joined Dec 15, 2005 Messages 3,215 Oct 27, 2020 #2 I assume you want to determine the inverse of the given functions [MATH]y = \sqrt[5]{x+2} + 2[/MATH] swap x and y ... [MATH]x = \sqrt[5]{y+2} + 2[/MATH] solve for y ... [MATH]x - 2 = \sqrt[5]{y+2}[/MATH] [MATH](x - 2)^5 = y+2[/MATH] [MATH]y = f^{-1}(x) = (x-2)^5 - 2[/MATH] you try the first one ...
I assume you want to determine the inverse of the given functions [MATH]y = \sqrt[5]{x+2} + 2[/MATH] swap x and y ... [MATH]x = \sqrt[5]{y+2} + 2[/MATH] solve for y ... [MATH]x - 2 = \sqrt[5]{y+2}[/MATH] [MATH](x - 2)^5 = y+2[/MATH] [MATH]y = f^{-1}(x) = (x-2)^5 - 2[/MATH] you try the first one ...