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Artemis01

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Jun 21, 2021
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Solve the equation 2 sin (theta + pi/3) -1 =0 for theta is more than or equal to 0 and theta is less than or equal to pi

what i have so far is 2sin(theta+pi/3)-1=0
2sin(theta+pi/3)=1
sin(theta+pi/3)=1/2
theta+pi/3=sin^-1(1/2)
= 30
theta = 30-pi/3
theta = 28.95
but that doesn't seem to be right so can someone please assist?
 
Artemis01 said:
Solve the equation 2 sin (theta + pi/3) -1 =0 for theta is more than or equal to 0 and theta is less than or equal to pi

what i have so far is 2sin(theta+pi/3)-1=0
2sin(theta+pi/3)=1
sin(theta+pi/3)=1/2
theta+pi/3=sin^-1(1/2)
= 30
theta = 30-pi/3
theta = 28.95
but that doesn't seem to be right so can someone please assist?
Click to expand...
You calculate:
2sin(theta+pi/3)=1
sin(theta+pi/3)=1/2
theta+pi/3=sin^-1(1/2)= π/6 or 5π/6

Θ = 5π/6 - π/3 = ?? ..........................you need to calculate in RADIANS
 
The angle \theta is in radians and you are working in degrees.
 
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