x^(2n+1)-?2x?^(n+1)+x I cannot figure out how to factor this equation.. please help!!!
T targus1990 New member Joined Feb 12, 2009 Messages 1 Feb 12, 2009 #1 x^(2n+1)-?2x?^(n+1)+x I cannot figure out how to factor this equation.. please help!!!
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Feb 12, 2009 #2 Start by factoring an \(\displaystyle x\). Then notice that what's left is a perfect square.
D Deleted member 4993 Guest Feb 13, 2009 #3 targus1990 said: x^(2n+1)-?2x?^(n+1)+x I cannot figure out how to factor this equation.. please help!!! No "equality(=)" sign exist in the problem statement - hence it is not an equation Click to expand... If the function to be factorized is as stated - then \(\displaystyle x^{2n+1} \, - \, (2x)^{n+1} \, + x \, = \, x\cdot [x^{2n} \, - \, 2\cdot(2x)^{n} \, + 1] \,\) no further factorization is possible.
targus1990 said: x^(2n+1)-?2x?^(n+1)+x I cannot figure out how to factor this equation.. please help!!! No "equality(=)" sign exist in the problem statement - hence it is not an equation Click to expand... If the function to be factorized is as stated - then \(\displaystyle x^{2n+1} \, - \, (2x)^{n+1} \, + x \, = \, x\cdot [x^{2n} \, - \, 2\cdot(2x)^{n} \, + 1] \,\) no further factorization is possible.