Point-Slope - Standard Form Equation

[asailors]

I need to use the point-slope form of the following equation and then right the equation in standard form:

Slope 6; through (2,2)

Here is my work:

y-2=6(x-2)

y-2=6x-12

The answer (in standard form) I get is: 6x-y=-10 but my textbook says: 6x-y=10.

I'm sure I'm missing the obvious, but what am I doing wrong?

 

[Mrspi]

I need to use the point-slope form of the following equation and then right the equation in standard form:

Slope 6; through (2,2)

Here is my work:

y-2=6(x-2)

y-2=6x-12

The answer (in standard form) I get is: 6x-y=-10 but my textbook says: 6x-y=10.

I'm sure I'm missing the obvious, but what am I doing wrong?

I guess in large part "what you are doing wrong" depends on how STANDARD FORM is defined.

In many texts, standard form is defined as

Ax + By = C

where A, B, and C are integers and where A is positive.

You've arrived at the point where you have

y - 2 = 6x - 12

or,
y = 6x - 10

You can subtract 6x from both sides:

-6x + y = -10

NOW...if you need the coefficient of x to be positive, you must multiply both sides of this equation by -1:

-1(-6x + y) = -1(-10)

6x - y = 10

There.....does that agree with the answer in your text?

 

[Denis]

I need to use the point-slope form of the following equation and then right the equation in standard form:
Slope 6; through (2,2)
Here is my work:
y-2=6(x-2)
y-2=6x-12
The answer (in standard form) I get is: 6x-y=-10 but my textbook says: 6x-y=10.

You simply made a mistake with "-10"; look at it again: should be +10