Find the prime numbers p>0
p+7=2x^2
p^2+7=2y^2 where x,y are integers
I noticed the last digit of p is 1 and it looks like 11 it is a solution. p=11, x=3, y=8
I don't how to solve it properly though.
p(p-1)=2(x-y)(x+y) but I don't think it's going anywhere.
Any hints, please?
Thank you!!
p+7=2x^2
p^2+7=2y^2 where x,y are integers
I noticed the last digit of p is 1 and it looks like 11 it is a solution. p=11, x=3, y=8
I don't how to solve it properly though.
p(p-1)=2(x-y)(x+y) but I don't think it's going anywhere.
Any hints, please?
Thank you!!