chelsea.vonderhaar
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- Joined
- Feb 15, 2009
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If i have (3d^-4)(5d^8) would i times 3 and 5 which is 15.. then have -4--8 which would be four?
15d^4 ?
15d^4 ?
chelsea.vonderhaar said:If i have (3d^-4)(5d^8) would i times 3 and 5 which is 15.. then have -4--8 which would be four?
15d^4 <<<< Correct
?
chelsea.vonderhaar said:Thank you very much!
If i have a^3 * a would it just be a^3 ?
You mean p^7 * q^5 * p^6, right? Then you're correct.chelsea.vonderhaar said:oh okay! So say if i had like..
p^7 * q^5 8 p^6..
i would add 7 and 6, not multiply them??
then it would be p^13 * q^5 ?