solve a system of equation by substition

bobisaka

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Dec 25, 2019
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How did they get 16/2??

I get:
(15/4)-(-1/2)=8
(15/4)-1(-1/2)=8
(15/4)(1/2)=8 <================ I am confused at this point by which strategy to use?

I don't know how they simplified it to 16/2 = 8


EDIT:

After redoing it, is there a typo in the textbook?

It should be the following: (15/2) + (1/2) = 8
 
Last edited:
(-)(-) = +
means
negative times negative = positive

[MATH]\frac{15}{2} - \frac{-1}{2} = \frac{15}{2} + \frac{1}{2} = \frac{16}{2} = 8[/MATH]
 
(-)(-) = +
means
negative times negative = positive

[MATH]\frac{15}{2} - \frac{-1}{2} = \frac{15}{2} + \frac{1}{2} = \frac{16}{2} = 8[/MATH]

I get that, If you look back at my post edit, there is a typo in the textbook which confused me.

Correct me I am wrong.
 
View attachment 25711

How did they get 16/2??

I get:
(15/4)-(-1/2)=8
(15/4)-1(-1/2)=8
(15/4)(1/2)=8 <================ I am confused at this point by which strategy to use?

I don't know how they simplified it to 16/2 = 8


EDIT:

After redoing it, is there a typo in the textbook?

It should be the following: (15/2) + (1/2) = 8
You are correct here - and -

there is a typo in the book, as you indicated.
 
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