How do you know that the function in question is a quadratic function?
I too graphed it and did not get any roots. I wonder which function I graphed!There's clearly a solution when graphing the equation.
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I did find a solution through the method of graphing. However, I'm wondering what's the required method of the OP.I too graphed it and did not get any roots. I wonder which function I graphed!
@bbb , What solution did you get?I did find a solution through the method of graphing. However, I'm wondering what's the required method of the OP.
You didn't graph the given equation. It has no Real solutions.I did find a solution through the method of graphing
@bbb , What solution did you get?
If you take the exponent of 7 to be (1-x) then there are two solutions → x = 1 and x = ~8
If you take the exponent of 7 to be (1+x) then there is no solution (according plot by WA).
You didn't graph the given equation. It has no Real solutions.
Yes, if we're talking about principal based roots, we have no real solutions.From wikipedia, "Unless specified otherwise, the principal root is often implied when talking about roots".