Solving Quadratic Equations that are not equal to 0

[froggomad]

I can solve auadratic equations where the quadratic isequal to 0 with no problem at all! However, I'm taking Algebra through independent study and this book has thrown a problem at me. It's giving me quadratic equations not equal to 0 with NO EXPLANATION on how to solve them. Can somebody please list the steps for me to solve these problems?

Example: -12x + 4 = -9x(sq)

Thanks in advance!

 

[royhaas]

Re-write it so it is equal to zero, then solve.

 

[froggomad]

-12x + 4 + 9x(sq)= 0

3x - 2 = 0

3x = -2

x = -2/3

-12(-2/3) = 8

8 + 4 = 12

-2/3 * -2/3 = 4/3

9 * 4/3 = 12

so 12 = 12

Ty very much for your help =)

 

[Denis]

-12x + 4 + 9x(sq)= 0
3x - 2 = 0
3x = -2
x = -2/3
-12(-2/3) = 8
8 + 4 = 12
-2/3 * -2/3 = 4/3
9 * 4/3 = 12
so 12 = 12

That's NOT correct, Froggy: 12 + 12 = 24, not 0
3x - 2 = 0
then 3x = 2, not -2

Make your life easier and show your equation this way, which is standard:
9x^2 - 12x + 4 = 0

x^2 means x squared.