Solving y/y+4-2/y=y+2/4 for y

[Stine]

y/y+4-2/y=y+2/4

I know you find the common deonominator which is y(y+4) right?
Well... when I am canceling out I am stuck in regards to y+2/4 and what I cancel out on this side of the problem?????

Thanks

 

[Mrspi]

Re: Solve for y Help me please!

y/y+4-2/y=y+2/4

I know you find the common deonominator which is y(y+4) right?
Well... when I am canceling out I am stuck in regards to y+2/4 and what I cancel out on this side of the problem?????

Thanks

4(y + 4) * [ (y + 2) / 4]

Looks like the 4's will cancel, leaving you with (y + 4)(y + 2) on the right side.

 

[Stine]

LOST...

Ok then I was doing the work totally wrong??? I was multiplying y(y+4). CAn I get a little more help with this one?

 

[Denis]

Re: Solve for y Help me please!

y/y+4-2/y=y+2/4

WHAT is that, Stine?
y / (y + 4) - 2/y = (y + 2) / 4 :?:

If you want help, please be clear ... USE BRACKETS :shock:

 

[stapel]

Ok then I was doing the work totally wrong?

It is difficult to trouble-shoot work which has not been posted.

Please reply showing all of your work and reasoning. Thank you.

Eliz.

 

[Stine]

[y/y+4]-[2/y]=[y+2/4]

Does this look better?????? :?:

 

[stapel]

[y/y+4]-[2/y]=[y+2/4]

Does this look better?????? :?:

What you have posted means the following:

. . . . .\(\displaystyle \L \frac{y}{y}\, +\, 4\, -\, \frac{2}{y}\, =\, y\, +\, \frac{2}{4}\)

Is that what you meant? Or did you mean something more along the lines of this:

. . . . .y/(y + 4) - 2/y = (y + 2)/4

...which also means the following?

. . . . .\(\displaystyle \L \frac{y}{y\, +\, 4}\, -\, \frac{2}{y}\, =\, \frac{y\, +\, 2}{4}\)

When you reply, please include all of your work and reasoning, so the tutors can see what method you are using and where you are getting stuck.

Thenk you.

Eliz.