the trigonometric identity to be proved is:
[math]\frac{2+2 \sin(x)}{\cos(x) + \sin(x) \cos(x)} = \frac{2}{\cos(x)}[/math]
my general approach is to try and simplify the more complicated side, and recognise any expressions that fit within the body of trigonometric identities known to me
but I am completely stumped here. I can see that I already have the goal expression embedded in the LHS which is my working side, but the extra terms suggest the identity is false??
I recognise the sin(x)cos(x) as writable in terms of sin(2x) but introducing a double angle into a single angle equation cant help.
thoughts?
[math]\frac{2+2 \sin(x)}{\cos(x) + \sin(x) \cos(x)} = \frac{2}{\cos(x)}[/math]
my general approach is to try and simplify the more complicated side, and recognise any expressions that fit within the body of trigonometric identities known to me
but I am completely stumped here. I can see that I already have the goal expression embedded in the LHS which is my working side, but the extra terms suggest the identity is false??
I recognise the sin(x)cos(x) as writable in terms of sin(2x) but introducing a double angle into a single angle equation cant help.
thoughts?