Trans formula help!

[yohanson77]

Hi, need some help on this one please. just a break down to grasp it

Q. Make 'b' the subject of the equation?

x = (square root) a(squared) - b(squared) /ay

thank you

 

[tkhunny]

You'll have to figure out how to type it better than that. What you have is very difficult to translate.

You can do square roots like a function, sqrt(stuff). The parentheses tell what is included.

You can use the caret (^) for exponents. "x-squared" would be "x^2".

You can add some spacing fopr clarity.

This makes the square root of the quantity x-squared less a-squared like this, sqrt(x^2 - a^2)

Or, you could learn just a little LaTeX.

 

[yohanson77]

Trans Formula help

You'll have to figure out how to type it better than that. What you have is very difficult to translate.

You can do square roots like a function, sqrt(stuff). The parentheses tell what is included.

You can use the caret (^) for exponents. "x-squared" would be "x^2".

You can add some spacing fopr clarity.

This makes the square root of the quantity x-squared less a-squared like this, sqrt(x^2 - a^2)

Or, you could learn just a little LaTeX.

Sorry tkhunny, try to do this on my phone. hope this is easier to understand:

Make b the subject of the equation:

x = sqrt(a^2 - b^2 / ay)

i've been told it's

b = sqrt(a^2 - ayx^2)

how do I work it out?

thank you again

 

[Mrspi]

You have

x = sqrt[(a<SUP>2</SUP> - b<SUP>2</SUP>) / (ay) ]

Square both sides of the equation to remove the radical:

x<SUP>2</SUP> = {sqrt[(a<SUP>2</SUP> - b<SUP>2</SUP>) / (ay)]}<SUP>2</SUP>

x<SUP>2</SUP> = (a<SUP>2</SUP> - b<SUP>2</SUP>) / (ay)

Multiply both sides by ay:

ayx<SUP>2</SUP> = a<SUP>2</SUP> - b<SUP>2</SUP>

add b<SUP>2</SUP> to both sides:

ayx<SUP>2</SUP> + b<SUP>2</SUP> = a<SUP>2</SUP>

Subtract ayx<SUP>2</SUP> from both sides:

b<SUP>2</SUP> = a<SUP>2</SUP> - ayx<SUP>2</SUP>

take the square root of both sides:

b = + sqrt(a<SUP>2</SUP> - ayx<SUP>2</SUP>)