LCKurtz
Full Member
- Joined
- May 3, 2019
- Messages
- 475
Back in the stone age I was taught to use the "dimensional unit method" in a chemistry course for such problems. It may be the only thing I remember from that course in 1959. But it is very handy for keeping track of where you are in such a problem. Below is how this problem would be set up:
[math]x \frac{ \text{ teragrams}}{\text{Funville year}} = \frac {23.6568988\text{mg} }{1\text{meter}^2\cdot1\text{sec}}\times \frac {31,536,000\text{sec}}{1\text{year}}\times \frac {390,200,000\text{meter}^2}{1\text{Funville}}\times\\ \frac{1\text{teragram}}{1,000,000,000,000,000\text{mg}}[/math]If I didn't make any mistakes, the units on the right side will cancel to match those on the left.
[math]x \frac{ \text{ teragrams}}{\text{Funville year}} = \frac {23.6568988\text{mg} }{1\text{meter}^2\cdot1\text{sec}}\times \frac {31,536,000\text{sec}}{1\text{year}}\times \frac {390,200,000\text{meter}^2}{1\text{Funville}}\times\\ \frac{1\text{teragram}}{1,000,000,000,000,000\text{mg}}[/math]If I didn't make any mistakes, the units on the right side will cancel to match those on the left.
