Using binomial formulas, please help me solve this

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Padma

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– 2x[2x(x – 1) – (x + 1)(2x – 1)]

I have the result. I only need to "see" the process to get there. I've tried a dozen times, without success :-(

Thanx A LOT in advance for your help :D)
 
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Padma said:
– 2x[2x(x – 1) – (x + 1)(2x – 1)]
I have the result. I only need to "see" the process to get there. I've tried a dozen times, without success
Click to expand...
\(\begin{gathered}
- 2x\left[ {2x(x - 1) - \left\{ {(x + 1)(2x - 1)} \right\}} \right] \hfill \\
- 2x\left[ {2{x^2} - 2x - \left\{ {2{x^2} + x - 1} \right\}} \right] \hfill \\
- 2x\left[ { - 3x + 1} \right] \hfill \\
6{x^2} - 2x \hfill \\
\end{gathered} \)...........................edited
 
Last edited by a moderator:
Hi. After solving the components in parenthesis, this is what I got:
-2x [2x2 - 2x - 2x2-1x +1] = 6x2 - 2x ......................edited
 
Last edited by a moderator:
According to my teacher, the result is supposed to be: 16x - 32
I don't know how to get there?
 
I know it's incorrect. Because it's the same result I got.
Like I said. I don't recognize any binomial formula there
 
Padma said:
According to my teacher, the result is supposed to be: 16x - 32
I don't know how to get there?
Click to expand...
S/he must be solving a different problem - your answer is correct (with slight formatting problem).
 
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