First are those "x"s multiplications or variables? It is a very bad idea to use "x" to mean multiplication in algebra!
Also does the square root apply to only the first "y" or to the entire expression. If yes to both of those then \(\displaystyle \sqrt{y(y^3)(y)}= \sqrt{y^{1 + 3+ 1}}= \sqrt{y^5}= (y^5)^{1/2}= y^{5/2}= y^{2.5}\)
IF the square root applied only to the first y THEN you would have \(\displaystyle \sqrt{y}(y^3)(y)= y^{1/2}(y^4)= y^{4.5}\).
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