Vincent_M05
New member
- Joined
- Dec 28, 2021
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- 6
Of courseFirst, I don't think you added the fractions correctly. Would you please show the intermediate steps?
To your answer your question, [math]\frac{9+2}{3}=\frac{11}{3}[/math]However,
[math]\frac{\sout{9}+2}{\sout{3}} \neq 5[/math]You can only cancel when both your numerators and denominators are composed of multiplications only.
[math]\frac{9*2}{3} =\frac{\sout{9}*2}{\sout{3}}=6[/math]
yep, big thanks to both of you. I followed your example and understood the problem, thanks a lot.To add to what BBB wrote consider this argument.
Note that in \(\displaystyle \dfrac{9}{3}+\dfrac{2}{3}\) that BOTH the 9 and the 2 are being divided by 3.
Now we know that \(\displaystyle \dfrac{9}{3}+\dfrac{2}{3}=\dfrac{9+2}{3} \neq\dfrac{9}{3} + 2 = 5\) since both the 9 and the 2 must be divided by 3
You should distribute that 3 in your final answer since *maybe* you could then factor the numerator and have a factor of 2, (x-1) and/or x+1. Does this make sense?Of course
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