Hi, I've been stumped on this question:
A chemist with two mixtures of a chemical and water, of 20% and 40% concentrations, wishes to mix the two so as to obtain 10 ounces of 32% concentrations. How much of each must he use?
I've been using X as amount of mix 1, and so X - 10 as mix 2. And using these variables I've been trying to make an equation, but am having no luck. The last equation I tried was: X/0.2 + X-10/0.4 = 10/.32
Help!?
A chemist with two mixtures of a chemical and water, of 20% and 40% concentrations, wishes to mix the two so as to obtain 10 ounces of 32% concentrations. How much of each must he use?
I've been using X as amount of mix 1, and so X - 10 as mix 2. And using these variables I've been trying to make an equation, but am having no luck. The last equation I tried was: X/0.2 + X-10/0.4 = 10/.32
Help!?